Optimal. Leaf size=322 \[ \frac {7 (3 b B-11 A c)}{48 b^3 c x^{3/2}}-\frac {b B-A c}{4 b c x^{3/2} \left (b+c x^2\right )^2}-\frac {3 b B-11 A c}{16 b^2 c x^{3/2} \left (b+c x^2\right )}-\frac {7 (3 b B-11 A c) \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{32 \sqrt {2} b^{15/4} \sqrt [4]{c}}+\frac {7 (3 b B-11 A c) \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{32 \sqrt {2} b^{15/4} \sqrt [4]{c}}-\frac {7 (3 b B-11 A c) \log \left (\sqrt {b}-\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}+\sqrt {c} x\right )}{64 \sqrt {2} b^{15/4} \sqrt [4]{c}}+\frac {7 (3 b B-11 A c) \log \left (\sqrt {b}+\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}+\sqrt {c} x\right )}{64 \sqrt {2} b^{15/4} \sqrt [4]{c}} \]
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Rubi [A]
time = 0.18, antiderivative size = 322, normalized size of antiderivative = 1.00, number of steps
used = 14, number of rules used = 11, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.423, Rules used = {1598, 468,
296, 331, 335, 217, 1179, 642, 1176, 631, 210} \begin {gather*} -\frac {7 (3 b B-11 A c) \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{32 \sqrt {2} b^{15/4} \sqrt [4]{c}}+\frac {7 (3 b B-11 A c) \text {ArcTan}\left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}+1\right )}{32 \sqrt {2} b^{15/4} \sqrt [4]{c}}-\frac {7 (3 b B-11 A c) \log \left (-\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}+\sqrt {b}+\sqrt {c} x\right )}{64 \sqrt {2} b^{15/4} \sqrt [4]{c}}+\frac {7 (3 b B-11 A c) \log \left (\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}+\sqrt {b}+\sqrt {c} x\right )}{64 \sqrt {2} b^{15/4} \sqrt [4]{c}}+\frac {7 (3 b B-11 A c)}{48 b^3 c x^{3/2}}-\frac {3 b B-11 A c}{16 b^2 c x^{3/2} \left (b+c x^2\right )}-\frac {b B-A c}{4 b c x^{3/2} \left (b+c x^2\right )^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 210
Rule 217
Rule 296
Rule 331
Rule 335
Rule 468
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 1598
Rubi steps
\begin {align*} \int \frac {x^{7/2} \left (A+B x^2\right )}{\left (b x^2+c x^4\right )^3} \, dx &=\int \frac {A+B x^2}{x^{5/2} \left (b+c x^2\right )^3} \, dx\\ &=-\frac {b B-A c}{4 b c x^{3/2} \left (b+c x^2\right )^2}+\frac {\left (-\frac {3 b B}{2}+\frac {11 A c}{2}\right ) \int \frac {1}{x^{5/2} \left (b+c x^2\right )^2} \, dx}{4 b c}\\ &=-\frac {b B-A c}{4 b c x^{3/2} \left (b+c x^2\right )^2}-\frac {3 b B-11 A c}{16 b^2 c x^{3/2} \left (b+c x^2\right )}-\frac {(7 (3 b B-11 A c)) \int \frac {1}{x^{5/2} \left (b+c x^2\right )} \, dx}{32 b^2 c}\\ &=\frac {7 (3 b B-11 A c)}{48 b^3 c x^{3/2}}-\frac {b B-A c}{4 b c x^{3/2} \left (b+c x^2\right )^2}-\frac {3 b B-11 A c}{16 b^2 c x^{3/2} \left (b+c x^2\right )}+\frac {(7 (3 b B-11 A c)) \int \frac {1}{\sqrt {x} \left (b+c x^2\right )} \, dx}{32 b^3}\\ &=\frac {7 (3 b B-11 A c)}{48 b^3 c x^{3/2}}-\frac {b B-A c}{4 b c x^{3/2} \left (b+c x^2\right )^2}-\frac {3 b B-11 A c}{16 b^2 c x^{3/2} \left (b+c x^2\right )}+\frac {(7 (3 b B-11 A c)) \text {Subst}\left (\int \frac {1}{b+c x^4} \, dx,x,\sqrt {x}\right )}{16 b^3}\\ &=\frac {7 (3 b B-11 A c)}{48 b^3 c x^{3/2}}-\frac {b B-A c}{4 b c x^{3/2} \left (b+c x^2\right )^2}-\frac {3 b B-11 A c}{16 b^2 c x^{3/2} \left (b+c x^2\right )}+\frac {(7 (3 b B-11 A c)) \text {Subst}\left (\int \frac {\sqrt {b}-\sqrt {c} x^2}{b+c x^4} \, dx,x,\sqrt {x}\right )}{32 b^{7/2}}+\frac {(7 (3 b B-11 A c)) \text {Subst}\left (\int \frac {\sqrt {b}+\sqrt {c} x^2}{b+c x^4} \, dx,x,\sqrt {x}\right )}{32 b^{7/2}}\\ &=\frac {7 (3 b B-11 A c)}{48 b^3 c x^{3/2}}-\frac {b B-A c}{4 b c x^{3/2} \left (b+c x^2\right )^2}-\frac {3 b B-11 A c}{16 b^2 c x^{3/2} \left (b+c x^2\right )}+\frac {(7 (3 b B-11 A c)) \text {Subst}\left (\int \frac {1}{\frac {\sqrt {b}}{\sqrt {c}}-\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{c}}+x^2} \, dx,x,\sqrt {x}\right )}{64 b^{7/2} \sqrt {c}}+\frac {(7 (3 b B-11 A c)) \text {Subst}\left (\int \frac {1}{\frac {\sqrt {b}}{\sqrt {c}}+\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{c}}+x^2} \, dx,x,\sqrt {x}\right )}{64 b^{7/2} \sqrt {c}}-\frac {(7 (3 b B-11 A c)) \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{b}}{\sqrt [4]{c}}+2 x}{-\frac {\sqrt {b}}{\sqrt {c}}-\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{c}}-x^2} \, dx,x,\sqrt {x}\right )}{64 \sqrt {2} b^{15/4} \sqrt [4]{c}}-\frac {(7 (3 b B-11 A c)) \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{b}}{\sqrt [4]{c}}-2 x}{-\frac {\sqrt {b}}{\sqrt {c}}+\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{c}}-x^2} \, dx,x,\sqrt {x}\right )}{64 \sqrt {2} b^{15/4} \sqrt [4]{c}}\\ &=\frac {7 (3 b B-11 A c)}{48 b^3 c x^{3/2}}-\frac {b B-A c}{4 b c x^{3/2} \left (b+c x^2\right )^2}-\frac {3 b B-11 A c}{16 b^2 c x^{3/2} \left (b+c x^2\right )}-\frac {7 (3 b B-11 A c) \log \left (\sqrt {b}-\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}+\sqrt {c} x\right )}{64 \sqrt {2} b^{15/4} \sqrt [4]{c}}+\frac {7 (3 b B-11 A c) \log \left (\sqrt {b}+\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}+\sqrt {c} x\right )}{64 \sqrt {2} b^{15/4} \sqrt [4]{c}}+\frac {(7 (3 b B-11 A c)) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{32 \sqrt {2} b^{15/4} \sqrt [4]{c}}-\frac {(7 (3 b B-11 A c)) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{32 \sqrt {2} b^{15/4} \sqrt [4]{c}}\\ &=\frac {7 (3 b B-11 A c)}{48 b^3 c x^{3/2}}-\frac {b B-A c}{4 b c x^{3/2} \left (b+c x^2\right )^2}-\frac {3 b B-11 A c}{16 b^2 c x^{3/2} \left (b+c x^2\right )}-\frac {7 (3 b B-11 A c) \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{32 \sqrt {2} b^{15/4} \sqrt [4]{c}}+\frac {7 (3 b B-11 A c) \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{32 \sqrt {2} b^{15/4} \sqrt [4]{c}}-\frac {7 (3 b B-11 A c) \log \left (\sqrt {b}-\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}+\sqrt {c} x\right )}{64 \sqrt {2} b^{15/4} \sqrt [4]{c}}+\frac {7 (3 b B-11 A c) \log \left (\sqrt {b}+\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}+\sqrt {c} x\right )}{64 \sqrt {2} b^{15/4} \sqrt [4]{c}}\\ \end {align*}
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Mathematica [A]
time = 0.54, size = 187, normalized size = 0.58 \begin {gather*} \frac {-\frac {4 b^{3/4} \left (-3 b B x^2 \left (11 b+7 c x^2\right )+A \left (32 b^2+121 b c x^2+77 c^2 x^4\right )\right )}{x^{3/2} \left (b+c x^2\right )^2}+\frac {21 \sqrt {2} (-3 b B+11 A c) \tan ^{-1}\left (\frac {\sqrt {b}-\sqrt {c} x}{\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}}\right )}{\sqrt [4]{c}}+\frac {21 \sqrt {2} (3 b B-11 A c) \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}}{\sqrt {b}+\sqrt {c} x}\right )}{\sqrt [4]{c}}}{192 b^{15/4}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.41, size = 173, normalized size = 0.54
method | result | size |
derivativedivides | \(-\frac {2 \left (\frac {\left (\frac {15}{32} A \,c^{2}-\frac {7}{32} b B c \right ) x^{\frac {5}{2}}+\frac {b \left (19 A c -11 B b \right ) \sqrt {x}}{32}}{\left (c \,x^{2}+b \right )^{2}}+\frac {7 \left (11 A c -3 B b \right ) \left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {x +\left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {b}{c}}}{x -\left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {b}{c}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {b}{c}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {b}{c}\right )^{\frac {1}{4}}}-1\right )\right )}{256 b}\right )}{b^{3}}-\frac {2 A}{3 b^{3} x^{\frac {3}{2}}}\) | \(173\) |
default | \(-\frac {2 \left (\frac {\left (\frac {15}{32} A \,c^{2}-\frac {7}{32} b B c \right ) x^{\frac {5}{2}}+\frac {b \left (19 A c -11 B b \right ) \sqrt {x}}{32}}{\left (c \,x^{2}+b \right )^{2}}+\frac {7 \left (11 A c -3 B b \right ) \left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {x +\left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {b}{c}}}{x -\left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {b}{c}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {b}{c}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {b}{c}\right )^{\frac {1}{4}}}-1\right )\right )}{256 b}\right )}{b^{3}}-\frac {2 A}{3 b^{3} x^{\frac {3}{2}}}\) | \(173\) |
risch | \(-\frac {2 A}{3 b^{3} x^{\frac {3}{2}}}-\frac {15 x^{\frac {5}{2}} A \,c^{2}}{16 b^{3} \left (c \,x^{2}+b \right )^{2}}+\frac {7 x^{\frac {5}{2}} B c}{16 b^{2} \left (c \,x^{2}+b \right )^{2}}-\frac {19 A \sqrt {x}\, c}{16 b^{2} \left (c \,x^{2}+b \right )^{2}}+\frac {11 B \sqrt {x}}{16 b \left (c \,x^{2}+b \right )^{2}}-\frac {77 \left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {2}\, A \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {b}{c}\right )^{\frac {1}{4}}}+1\right ) c}{64 b^{4}}-\frac {77 \left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {2}\, A \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {b}{c}\right )^{\frac {1}{4}}}-1\right ) c}{64 b^{4}}-\frac {77 \left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {2}\, A \ln \left (\frac {x +\left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {b}{c}}}{x -\left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {b}{c}}}\right ) c}{128 b^{4}}+\frac {21 \left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {2}\, B \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {b}{c}\right )^{\frac {1}{4}}}+1\right )}{64 b^{3}}+\frac {21 \left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {2}\, B \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {b}{c}\right )^{\frac {1}{4}}}-1\right )}{64 b^{3}}+\frac {21 \left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {2}\, B \ln \left (\frac {x +\left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {b}{c}}}{x -\left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {b}{c}}}\right )}{128 b^{3}}\) | \(357\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.50, size = 285, normalized size = 0.89 \begin {gather*} \frac {7 \, {\left (3 \, B b c - 11 \, A c^{2}\right )} x^{4} - 32 \, A b^{2} + 11 \, {\left (3 \, B b^{2} - 11 \, A b c\right )} x^{2}}{48 \, {\left (b^{3} c^{2} x^{\frac {11}{2}} + 2 \, b^{4} c x^{\frac {7}{2}} + b^{5} x^{\frac {3}{2}}\right )}} + \frac {7 \, {\left (\frac {2 \, \sqrt {2} {\left (3 \, B b - 11 \, A c\right )} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} b^{\frac {1}{4}} c^{\frac {1}{4}} + 2 \, \sqrt {c} \sqrt {x}\right )}}{2 \, \sqrt {\sqrt {b} \sqrt {c}}}\right )}{\sqrt {b} \sqrt {\sqrt {b} \sqrt {c}}} + \frac {2 \, \sqrt {2} {\left (3 \, B b - 11 \, A c\right )} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} b^{\frac {1}{4}} c^{\frac {1}{4}} - 2 \, \sqrt {c} \sqrt {x}\right )}}{2 \, \sqrt {\sqrt {b} \sqrt {c}}}\right )}{\sqrt {b} \sqrt {\sqrt {b} \sqrt {c}}} + \frac {\sqrt {2} {\left (3 \, B b - 11 \, A c\right )} \log \left (\sqrt {2} b^{\frac {1}{4}} c^{\frac {1}{4}} \sqrt {x} + \sqrt {c} x + \sqrt {b}\right )}{b^{\frac {3}{4}} c^{\frac {1}{4}}} - \frac {\sqrt {2} {\left (3 \, B b - 11 \, A c\right )} \log \left (-\sqrt {2} b^{\frac {1}{4}} c^{\frac {1}{4}} \sqrt {x} + \sqrt {c} x + \sqrt {b}\right )}{b^{\frac {3}{4}} c^{\frac {1}{4}}}\right )}}{128 \, b^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 809 vs.
\(2 (238) = 476\).
time = 2.62, size = 809, normalized size = 2.51 \begin {gather*} -\frac {84 \, {\left (b^{3} c^{2} x^{6} + 2 \, b^{4} c x^{4} + b^{5} x^{2}\right )} \left (-\frac {81 \, B^{4} b^{4} - 1188 \, A B^{3} b^{3} c + 6534 \, A^{2} B^{2} b^{2} c^{2} - 15972 \, A^{3} B b c^{3} + 14641 \, A^{4} c^{4}}{b^{15} c}\right )^{\frac {1}{4}} \arctan \left (\frac {\sqrt {b^{8} \sqrt {-\frac {81 \, B^{4} b^{4} - 1188 \, A B^{3} b^{3} c + 6534 \, A^{2} B^{2} b^{2} c^{2} - 15972 \, A^{3} B b c^{3} + 14641 \, A^{4} c^{4}}{b^{15} c}} + {\left (9 \, B^{2} b^{2} - 66 \, A B b c + 121 \, A^{2} c^{2}\right )} x} b^{11} c \left (-\frac {81 \, B^{4} b^{4} - 1188 \, A B^{3} b^{3} c + 6534 \, A^{2} B^{2} b^{2} c^{2} - 15972 \, A^{3} B b c^{3} + 14641 \, A^{4} c^{4}}{b^{15} c}\right )^{\frac {3}{4}} + {\left (3 \, B b^{12} c - 11 \, A b^{11} c^{2}\right )} \sqrt {x} \left (-\frac {81 \, B^{4} b^{4} - 1188 \, A B^{3} b^{3} c + 6534 \, A^{2} B^{2} b^{2} c^{2} - 15972 \, A^{3} B b c^{3} + 14641 \, A^{4} c^{4}}{b^{15} c}\right )^{\frac {3}{4}}}{81 \, B^{4} b^{4} - 1188 \, A B^{3} b^{3} c + 6534 \, A^{2} B^{2} b^{2} c^{2} - 15972 \, A^{3} B b c^{3} + 14641 \, A^{4} c^{4}}\right ) + 21 \, {\left (b^{3} c^{2} x^{6} + 2 \, b^{4} c x^{4} + b^{5} x^{2}\right )} \left (-\frac {81 \, B^{4} b^{4} - 1188 \, A B^{3} b^{3} c + 6534 \, A^{2} B^{2} b^{2} c^{2} - 15972 \, A^{3} B b c^{3} + 14641 \, A^{4} c^{4}}{b^{15} c}\right )^{\frac {1}{4}} \log \left (7 \, b^{4} \left (-\frac {81 \, B^{4} b^{4} - 1188 \, A B^{3} b^{3} c + 6534 \, A^{2} B^{2} b^{2} c^{2} - 15972 \, A^{3} B b c^{3} + 14641 \, A^{4} c^{4}}{b^{15} c}\right )^{\frac {1}{4}} - 7 \, {\left (3 \, B b - 11 \, A c\right )} \sqrt {x}\right ) - 21 \, {\left (b^{3} c^{2} x^{6} + 2 \, b^{4} c x^{4} + b^{5} x^{2}\right )} \left (-\frac {81 \, B^{4} b^{4} - 1188 \, A B^{3} b^{3} c + 6534 \, A^{2} B^{2} b^{2} c^{2} - 15972 \, A^{3} B b c^{3} + 14641 \, A^{4} c^{4}}{b^{15} c}\right )^{\frac {1}{4}} \log \left (-7 \, b^{4} \left (-\frac {81 \, B^{4} b^{4} - 1188 \, A B^{3} b^{3} c + 6534 \, A^{2} B^{2} b^{2} c^{2} - 15972 \, A^{3} B b c^{3} + 14641 \, A^{4} c^{4}}{b^{15} c}\right )^{\frac {1}{4}} - 7 \, {\left (3 \, B b - 11 \, A c\right )} \sqrt {x}\right ) - 4 \, {\left (7 \, {\left (3 \, B b c - 11 \, A c^{2}\right )} x^{4} - 32 \, A b^{2} + 11 \, {\left (3 \, B b^{2} - 11 \, A b c\right )} x^{2}\right )} \sqrt {x}}{192 \, {\left (b^{3} c^{2} x^{6} + 2 \, b^{4} c x^{4} + b^{5} x^{2}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.56, size = 304, normalized size = 0.94 \begin {gather*} \frac {7 \, \sqrt {2} {\left (3 \, \left (b c^{3}\right )^{\frac {1}{4}} B b - 11 \, \left (b c^{3}\right )^{\frac {1}{4}} A c\right )} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {b}{c}\right )^{\frac {1}{4}} + 2 \, \sqrt {x}\right )}}{2 \, \left (\frac {b}{c}\right )^{\frac {1}{4}}}\right )}{64 \, b^{4} c} + \frac {7 \, \sqrt {2} {\left (3 \, \left (b c^{3}\right )^{\frac {1}{4}} B b - 11 \, \left (b c^{3}\right )^{\frac {1}{4}} A c\right )} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {b}{c}\right )^{\frac {1}{4}} - 2 \, \sqrt {x}\right )}}{2 \, \left (\frac {b}{c}\right )^{\frac {1}{4}}}\right )}{64 \, b^{4} c} + \frac {7 \, \sqrt {2} {\left (3 \, \left (b c^{3}\right )^{\frac {1}{4}} B b - 11 \, \left (b c^{3}\right )^{\frac {1}{4}} A c\right )} \log \left (\sqrt {2} \sqrt {x} \left (\frac {b}{c}\right )^{\frac {1}{4}} + x + \sqrt {\frac {b}{c}}\right )}{128 \, b^{4} c} - \frac {7 \, \sqrt {2} {\left (3 \, \left (b c^{3}\right )^{\frac {1}{4}} B b - 11 \, \left (b c^{3}\right )^{\frac {1}{4}} A c\right )} \log \left (-\sqrt {2} \sqrt {x} \left (\frac {b}{c}\right )^{\frac {1}{4}} + x + \sqrt {\frac {b}{c}}\right )}{128 \, b^{4} c} - \frac {2 \, A}{3 \, b^{3} x^{\frac {3}{2}}} + \frac {7 \, B b c x^{\frac {5}{2}} - 15 \, A c^{2} x^{\frac {5}{2}} + 11 \, B b^{2} \sqrt {x} - 19 \, A b c \sqrt {x}}{16 \, {\left (c x^{2} + b\right )}^{2} b^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.45, size = 888, normalized size = 2.76 \begin {gather*} -\frac {\frac {2\,A}{3\,b}+\frac {11\,x^2\,\left (11\,A\,c-3\,B\,b\right )}{48\,b^2}+\frac {7\,c\,x^4\,\left (11\,A\,c-3\,B\,b\right )}{48\,b^3}}{b^2\,x^{3/2}+c^2\,x^{11/2}+2\,b\,c\,x^{7/2}}-\frac {\mathrm {atan}\left (\frac {\frac {\left (11\,A\,c-3\,B\,b\right )\,\left (\sqrt {x}\,\left (97140736\,A^2\,b^9\,c^5-52985856\,A\,B\,b^{10}\,c^4+7225344\,B^2\,b^{11}\,c^3\right )-\frac {7\,\left (11\,A\,c-3\,B\,b\right )\,\left (80740352\,A\,b^{13}\,c^4-22020096\,B\,b^{14}\,c^3\right )}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}\right )\,7{}\mathrm {i}}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}+\frac {\left (11\,A\,c-3\,B\,b\right )\,\left (\sqrt {x}\,\left (97140736\,A^2\,b^9\,c^5-52985856\,A\,B\,b^{10}\,c^4+7225344\,B^2\,b^{11}\,c^3\right )+\frac {7\,\left (11\,A\,c-3\,B\,b\right )\,\left (80740352\,A\,b^{13}\,c^4-22020096\,B\,b^{14}\,c^3\right )}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}\right )\,7{}\mathrm {i}}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}}{\frac {7\,\left (11\,A\,c-3\,B\,b\right )\,\left (\sqrt {x}\,\left (97140736\,A^2\,b^9\,c^5-52985856\,A\,B\,b^{10}\,c^4+7225344\,B^2\,b^{11}\,c^3\right )-\frac {7\,\left (11\,A\,c-3\,B\,b\right )\,\left (80740352\,A\,b^{13}\,c^4-22020096\,B\,b^{14}\,c^3\right )}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}\right )}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}-\frac {7\,\left (11\,A\,c-3\,B\,b\right )\,\left (\sqrt {x}\,\left (97140736\,A^2\,b^9\,c^5-52985856\,A\,B\,b^{10}\,c^4+7225344\,B^2\,b^{11}\,c^3\right )+\frac {7\,\left (11\,A\,c-3\,B\,b\right )\,\left (80740352\,A\,b^{13}\,c^4-22020096\,B\,b^{14}\,c^3\right )}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}\right )}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}}\right )\,\left (11\,A\,c-3\,B\,b\right )\,7{}\mathrm {i}}{32\,{\left (-b\right )}^{15/4}\,c^{1/4}}-\frac {7\,\mathrm {atan}\left (\frac {\frac {7\,\left (11\,A\,c-3\,B\,b\right )\,\left (\sqrt {x}\,\left (97140736\,A^2\,b^9\,c^5-52985856\,A\,B\,b^{10}\,c^4+7225344\,B^2\,b^{11}\,c^3\right )-\frac {\left (11\,A\,c-3\,B\,b\right )\,\left (80740352\,A\,b^{13}\,c^4-22020096\,B\,b^{14}\,c^3\right )\,7{}\mathrm {i}}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}\right )}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}+\frac {7\,\left (11\,A\,c-3\,B\,b\right )\,\left (\sqrt {x}\,\left (97140736\,A^2\,b^9\,c^5-52985856\,A\,B\,b^{10}\,c^4+7225344\,B^2\,b^{11}\,c^3\right )+\frac {\left (11\,A\,c-3\,B\,b\right )\,\left (80740352\,A\,b^{13}\,c^4-22020096\,B\,b^{14}\,c^3\right )\,7{}\mathrm {i}}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}\right )}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}}{\frac {\left (11\,A\,c-3\,B\,b\right )\,\left (\sqrt {x}\,\left (97140736\,A^2\,b^9\,c^5-52985856\,A\,B\,b^{10}\,c^4+7225344\,B^2\,b^{11}\,c^3\right )-\frac {\left (11\,A\,c-3\,B\,b\right )\,\left (80740352\,A\,b^{13}\,c^4-22020096\,B\,b^{14}\,c^3\right )\,7{}\mathrm {i}}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}\right )\,7{}\mathrm {i}}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}-\frac {\left (11\,A\,c-3\,B\,b\right )\,\left (\sqrt {x}\,\left (97140736\,A^2\,b^9\,c^5-52985856\,A\,B\,b^{10}\,c^4+7225344\,B^2\,b^{11}\,c^3\right )+\frac {\left (11\,A\,c-3\,B\,b\right )\,\left (80740352\,A\,b^{13}\,c^4-22020096\,B\,b^{14}\,c^3\right )\,7{}\mathrm {i}}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}\right )\,7{}\mathrm {i}}{64\,{\left (-b\right )}^{15/4}\,c^{1/4}}}\right )\,\left (11\,A\,c-3\,B\,b\right )}{32\,{\left (-b\right )}^{15/4}\,c^{1/4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
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